Q. The temperature of an object is $60^{\circ} C$. Its value in Fahrenheit scale is
Solution:
Let $T_F$ be temperature on Fahrenheit scale corresponding to $60^{\circ} C$ on Celsius scale. Then
$\frac{60-0}{100-0} = \frac{T_{F} -32}{212 -32} $
$ \frac{3}{5} = \frac{T_{F } - 32}{180}$
$ 5T_{F} - 160 = 540$
$ 5T_{F} = 700 $ or $T_{F} = \frac{700}{5}^{\circ}F = 140^{\circ} F$
