Question

The temperature gradient in a $\text{0.5} \, m$ long rod is $80 \,{}^\circ C \, m^{- 1}$ . If the temperature of the hotter end of the rod is $30 \,{}^\circ C$ , then the temperature of the cooler end is

• A. $40^\circ C$
• B. $-10 \,{}^\circ C$
• C. $10^\circ C$
• D. $0^\circ C$

Answer 1

Answer: (B)

$\Rightarrow \frac{d T}{d x}=80$
$\Rightarrow \frac{T_{2} - T_{1}}{l}=80$
$\Rightarrow \frac{30 - T_{1}}{0.5}=80$
$\Rightarrow 30-T_{1}=40$
$\Rightarrow T_{1}=-10 \,{}^\circ C$