1. Tardigrade
  2. Question
  3. Chemistry
  4. The table below gives the results of three titrations carried out with 0.200 M HCl to determine the molarity of a given NaOH solution using phenolphthalein as indicator. NaOH was taken in the burette and HCl was taken in a conical flask for the titrations Titration No. V HCl ( mL ) NaOH ( mL ) M NaOH mol / dm 3 I 21.4 19.3 0.222 II 18.6 16.8 0.221 III 22.2 21.1 0.210 The actual molarity of the prepared NaOH solution was 0.220 mol dm-3. Which among the following could be the reason for the wrong value obtained in titration III?

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Q. The table below gives the results of three titrations carried out with 0.200 M HCl to determine the molarity of a given NaOH solution using phenolphthalein as indicator. NaOH was taken in the burette and HCl was taken in a conical flask for the titrations

Titration No. $V _{ HCl ( mL )}$ $NaOH ( mL )$ $M _{ NaOH } mol / dm ^{3}$
I 21.4 19.3 0.222
II 18.6 16.8 0.221
III 22.2 21.1 0.210


The actual molarity of the prepared NaOH solution was 0.220 mol dm-3. Which among the following could be the reason for the wrong value obtained in titration III?

NTA AbhyasNTA Abhyas 2020Redox Reactions

Solution:

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$\left[O H^{-}\right]=\frac{n_{O H^{-}}}{V_{O H^{-}}}=\frac{n_{a c i d}}{V_{N a O H}}=\frac{\left[H C l\right] V_{H C l}}{V_{N a O H}}=0.21M < 0.220$