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  4. The system starts from rest and A attains a velocity of 5 m/s after it has moved 5 m towards right. Assuming the arrangement to be frictionless everywhere and pulley and strings to be light, the value of the constant force F applied on A is: <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/b2828cac183c3ce64df6b8459b0b2a95-.png />

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Q. The system starts from rest and A attains a velocity of 5 m/s after it has moved 5 m towards right. Assuming the arrangement to be frictionless everywhere and pulley and strings to be light, the value of the constant force F applied on A is:
image

Laws of Motion

Solution:

$a=\frac{V^{2}}{2s} =\frac{25}{10}$
$=2.5\,m/s^{2}$
image
For 6 kg :$-F-2T=6a$
For 2 kg : $-T-2g=2(2a)$
From (1) and (2) $F= 75\, N $