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Physics
The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap bubble of surface area 40 cm2, (in J) is
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Q. The surface tension of soap solution is $0.03\, N/m$. The work done in blowing to form a soap bubble of surface area $40 \, cm^2, (in\, J)$ is
BITSAT
BITSAT 2008
A
$ 1.2 \times 10^{-4} $
15%
B
$ 2.4 \times 10^{-4} $
52%
C
$ 12 \times 10^{-4} $
22%
D
$ 24 \times 10^{-4} $
12%
Solution:
In case of soap bubble
$W = T \times 2 \times \Delta A$
$ = 0.03 \times 2 \times 40 \times 10^{-4}$
$ = 2.4 \times 10^{-4} \, J $