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Q. The surface density of a spherical conductor is $\sigma_1$, and the electric field on its surface is $E_1$. The surface density of an infinite cylindrical conductor is $\sigma_2$ and the electric field on its surface is $E_2$. Which of the following relation is correct ?

Electrostatic Potential and Capacitance

Solution:

$E_1 = \frac{\sigma_1}{\varepsilon_2} $ also $E_2 = \frac{\sigma_2}{\varepsilon_0}$ . Hence $\frac{E_1}{E_2} = \frac{\sigma_1}{\sigma_2}$