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Q. The sun subtends an angle of half a degree at the pole of a concave mirror which has a radius of curvature of 15 m. Then the size (diameter) of the image of the sun formed by the concave mirror is

JamiaJamia 2009

Solution:

$ \theta =\frac{diameter\text{ }of\text{ }sun}{distance\text{ }of\text{ }sun} $ $ \theta =\frac{diameter\text{ }of\text{ }image}{focal\text{ }length\text{ }of\text{ }concave\text{ }mirror} $ $ \frac{1}{2}\times \frac{\pi }{180}=\frac{diameter\text{ }of\text{ }image}{7.5m} $ $ \therefore $ Diameter of image $ =\frac{\pi }{360}\times 7.5\,m $ $ =\frac{3.14\times 7.5}{360}\times 100\,cm $ $ =6.55cm $