Q. The sun (diameter $D$ ) subtends an angle $\theta $ radian at the pole of a concave mirror of focal length $f$ . The diameter of the image of the sun formed by the mirror is:
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Solution:
$tan\left(\frac{\theta }{2}\right)=\frac{A ' F}{P F}=\frac{A ' F}{f}A'F=f(tan\left(\frac{\theta }{2})\right)A'F=f(\frac{\theta }{2})A'B'=2A'F=f(\theta) $