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Mathematics
The sum underbrace(666...6)2n digits + underbrace(888...8)n digitsis equal to
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Q. The sum $\underbrace{(666...6)^{2}}_{n\,digits}$ +$\underbrace{(888...8)}_{n\,digits}$is equal to
Principle of Mathematical Induction
A
$\frac{4}{9}\left(10^{n}-1\right)^{2}$
B
$\frac{4}{9}\left(10^{n}-1\right)$
C
$\frac{4}{9}\left(10^{2n}-1\right)$
D
$4\left(10^{n}-1\right)$
Solution:
Correct answer is (c) $\frac{4}{9}\left(10^{2n}-1\right)$