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Q. The sum of the coefficients in the expansion of $(1 - x )^{10}$ is

Binomial Theorem

Solution:

$\left(1-x\right)^{10} = 1-\,{}^{10}C_{1}\,x+\,{}^{10}C_{2}\,x^{2}-\,{}^{10}C_{3}\,x^{3} + ...$
$...+\,{}^{10}C_{10}\,x^{10}$
$\therefore $ Sum of coefficients $= 1 -\,{}^{10}C_{1} + \,{}^{10}C_{2}-\,{}^{10}C_{3}+...+\,{}^{10}C_{10}$
$=0$