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  4. The sum of proper divisors of 72 (1 and 72 are excluded) is equal to

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Q. The sum of proper divisors of 72 (1 and 72 are excluded) is equal to

Permutations and Combinations

Solution:

Proper divisors of $72$ are $2, 3, 4, 8, 9, 12, 18, 24, 36$
Their sum
$= 2+ 3 + 4 + 6 + 8 + 9 + 1 2 + 18 + 24 +26$
$= 122$