Question

The sum of all the divisors of $2^5 \cdot 3^7 \cdot 5^3 \cdot 7^2$ is

• A. $2^6 \cdot 3^8 \cdot 5^4 \cdot 7^3-2 \cdot 3 \cdot 5 \cdot 7$
• B. $2^6 \cdot 3^8 \cdot 5^4 \cdot 7^3$
• C. $2^6 \cdot 3^8 \cdot 5^4 \cdot 7^3-1$
• D. $\frac{\left(2^6-1\right)\left(3^8-1\right)\left(5^4-1\right)\left(7^3-1\right)}{2.4 .6}$

Answer 1

Answer: (D)

Correct answer is (d) $\frac{\left(2^6-1\right)\left(3^8-1\right)\left(5^4-1\right)\left(7^3-1\right)}{2.4 .6}$