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Q.
The sum of all numbers greater than $1000$ formed by using digits $1$, $3$, $5$, $7$ no digit being repeated in any number is
Permutations and Combinations
Solution:
Reqd. sum $= 3 !\left[1+3+5+7\right]\left[1+10+100+1000\right]$
$=96\left(1111\right)=106, 656$
[$\because$ each digit occurs $3\,!$ times in unit place tens place, hundreds place and thousands place.]