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Q. The successive ionization energies for element $X$ is given below
$IE _{1}: 250 kJ mol ^{-1}$
$IE _{2}: 820 kJ mol ^{-1}$
$IE _{3}: 1100 kJ mol ^{-1}$
$IE _{4}: 1400 kJ mol ^{-1}$
Find out the number of valence electrons for the element $X$

Classification of Elements and Periodicity in Properties

Solution:

Difference between $IE _{1}$ and $IE _{2}$ is high then the number of valence electron in the element is one.