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Chemistry
The substance A when dissolved in solvent B shows the molecular mass corresponding to A3. The van’t Hoff factor will be
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Q. The substance A when dissolved in solvent B shows the molecular mass corresponding to $A_3$. The van’t Hoff factor will be
Solutions
A
1
6%
B
2
6%
C
3
6%
D
1/3
81%
Solution:
$\underset{1-\alpha}{3 A } \rightarrow \underset{\alpha / 3}{ A _{3}}$
$i =1-\alpha=\alpha / 3$
$(\alpha=100 \%)$
$=1-1+\frac{1}{3}=\frac{1}{3}$