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Q. The substance A when dissolved in solvent B shows the molecular mass corresponding to $A_3$. The van’t Hoff factor will be

Solutions

Solution:

$\underset{1-\alpha}{3 A } \rightarrow \underset{\alpha / 3}{ A _{3}}$
$i =1-\alpha=\alpha / 3$
$(\alpha=100 \%)$
$=1-1+\frac{1}{3}=\frac{1}{3}$