1. Tardigrade
  2. Question
  3. Chemistry
  4. The structure of PF5 molecule is:

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The structure of $ P{{F}_{5}} $ molecule is:

JIPMERJIPMER 2001Chemical Bonding and Molecular Structure

Solution:

$ {}_{15}P=1{{s}^{2}},\,2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{3}}3{{d}^{0}} $ P in excited state =
$ P{{F}_{5}}=\begin{matrix} \underset{{{F}_{{{(2px)}^{1}}}}}{\mathop{\underset{|}{\mathop{{{(s{{p}^{3}}d)}^{1}}}}\,}}\, & \underset{{{F}_{{{(2px)}^{1}}}}}{\mathop{\underset{|}{\mathop{{{(s{{p}^{3}}d)}^{1}}}}\,}}\, & \underset{{{F}_{{{(2px)}^{1}}}}}{\mathop{\underset{|}{\mathop{{{(s{{p}^{3}}d)}^{1}}}}\,}}\, & \underset{{{F}_{{{(2px)}^{1}}}}}{\mathop{\underset{|}{\mathop{{{(s{{p}^{3}}d)}^{1}}}}\,}}\, & \underset{{{F}_{{{(2px)}^{1}}}}}{\mathop{\underset{|}{\mathop{{{(s{{p}^{3}}d)}^{1}}}}\,}}\, \\ \end{matrix} $
Thus, due to $ s{{p}^{3}}d\text{-} $ hybridization, $ P{{F}_{5}} $ molecule has trigonal bipyramidal geometry.

Solution Image Solution Image