Question

The strength of $H_2O_2$ (in g/L) in $11.2$ volume solution of $H_2O_2 $ is

• A. 17
• B. 51
• C. 34
• D. 85

Answer 1

Answer: (C)

By definition, $1 \, L$ of $11.2$ volume solution of $H_2O_2$ on decomposition gives $11.2\, L$ of oxygen at $NTP$
$\underset{2 \times 34 = 68 \, g}{H_2O_2} \rightarrow 2H_2O + O_2 $
$22.4 \,L$ at NTP
Hence $11.2 \,L$ of oxygen will be obtained from
$H_2O_2 = \frac{68}{22.4} \times 11.2 = 34 \,g$
$\therefore $ Strength of $11.2$ volume of solution
$ = 34\, g/L$