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Q.
The straight lines $7 x-2 y+10=0$ and $7 x+2 y-10= 0$ form an isosceles triangle with the line $y=2$. The area of this triangle is equal to
Straight Lines
Solution:
We have
$B \equiv\left(\frac{6}{7}, 2\right), C \equiv\left(-\frac{6}{7}, 2\right)$
or $ B C=\frac{12}{7}, A D=3$
$\therefore \Delta_{A B C}=\frac{1}{2} \times \frac{12}{7} \times 3=\frac{18}{7}$ sq. units
