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Q. The straight line $\frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}$ is ...A.... Here, A refers to

Three Dimensional Geometry

Solution:

Given line is $\frac{x-3}{3}=\frac{y-2}{1}=\frac{z-1}{0}$
Direction ratios of the line are $3,1,0$
Direction ratios of $Z$-axis are $0,0,1$
$a_1 a_2 +b_1 b_2+c_1 c_2 $
$ =(3)(0)+(1)(0)+(0)(1)=0$
Hence, given line is perpendicular to $Z$-axis.