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  4. The stopping potential V0 (in volt) as a function of frequency (n) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be: (Given: Planck's constant (h) = 6.63 × 10-34 Js, electron charge e = 1.6 × 10-19 C)

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Q. The stopping potential $V_0$ (in volt) as a function of frequency (n) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be :
(Given : Planck's constant (h) = 6.63 $\times $ 10$^{-34}$ Js, electron charge e = 1.6 $\times $ 10$^{-19}$ C)Physics Question Image

JEE MainJEE Main 2019Dual Nature of Radiation and Matter

Solution:

$hv = \phi +ev_{0} $
$ v_{0 } =\frac{hv}{e} - \frac{\phi}{e} $
$ v_{0} $ is zero for $ v=4 \times10^{14} Hz $
$ 0 = \frac{hv}{e} - \frac{\phi}{e} \Rightarrow \phi = hv $
$ = \frac{6.63 \times10^{-34} \times4 \times10^{14}}{1.6 \times10^{-19}} = 1.66 \,ev$