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Q. The stopping potential $V_{0}$ (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure The work function (in eV) of sodium, from the data plotted in the figure, will be :
(Given : Planck’s constant $(h)=6.63 \times 10^{-34}\,Js$, electron charge $e =1.6 \times 10^{-19}\,C)$
image

Dual Nature of Radiation and Matter

Solution:

$f_{0}=4\times 10^{14}\,Hz$
$W_{0} = hf_{0} = 6.63 \times 10^{-34} \times (4 \times 10^{14})\,J$
$\frac{6.63 \times 10^{-34} \times 6 \times 10^{14}} {1.6 \times 10^{-19}} $
$=1.66\,eV$