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Q. The stopping potential for photoelect ons from a metal surface is $V_1$ when monochromatic light of frequency $v_1$ is incident on it. The stopping potential becomes $V_2$ when monochromatic light of another frequency is incident on the same metal surface. If $h$ be the Planck’s constant and $e$ be the charge of an electron, then the frequency of light in the second case is

WBJEEWBJEE 2013Dual Nature of Radiation and Matter

Solution:

Here, $h v_{1}=\phi_{0}=e V_{1} .... (i) $
and $h v_{2}=\phi_{0}+e V_{2}$..... (ii)
From Eqs. (i) and (ii), we have $h\left( v _{2}- v _{1}\right)= e \left(V_{2}-V_{1}\right)$
$\Rightarrow v_{2}=\frac{e}{h}\left(V_{2}-V_{1}\right)+v_{1}$