1. Tardigrade
  2. Question
  3. Chemistry
  4. The standard reduction potential at 25° C of the reaction, 2H2 O + 2e- leftharpoons H2 + 2OH-, is -0.8277 V. Calculate the equilibrium constant for the reaction, 2H2 O leftharpoons H3 O+ + OH- at 25° C

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Q. The standard reduction potential at $25^\circ C$ of the reaction,
$ 2H_2 O + 2e^- \rightleftharpoons H_2 + 2OH^-,$ is $-0.8277 \,V$. Calculate the
equilibrium constant for the reaction,
$ 2H_2 O \rightleftharpoons H_3 O^+\,+ OH^-$ at $25^\circ C$

IIT JEEIIT JEE 1989Electrochemistry

Solution:

image
$ E^\circ = 0.0592\, log\, K$
$\Rightarrow \log\, K = \frac{-.08277}{0.0592}=-13.98$
$\Rightarrow K = 1.04 \times 10^{-14} $