1. Tardigrade
  2. Question
  3. Chemistry
  4. The standard free energy change (Δ G °) for 50 % dissociation of N 2 O 4 into NO 2 at 27° C and 1 atm pressure is -x J mol -1. The value of x is (Nearest Integer) [Given: R =8.31 J K -1 mol -1, log 1.33=0.1239 ln 10=2.3]

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Q. The standard free energy change $\left(\Delta G ^{\circ}\right)$ for $50 \%$ dissociation of $N _{2} O _{4}$ into $NO _{2}$ at $27^{\circ} C$ and $1$ atm pressure is $-x \,J \,mol ^{-1}$. The value of $x$ is ________(Nearest Integer)
[Given : $R =8.31 \,J \,K ^{-1} mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$

JEE MainJEE Main 2022Thermodynamics

Solution:

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$k _{ P }=\frac{\left(\frac{1}{1.5} \times 1\right)^{2}}{\left(\frac{0.5}{1.5} \times 1\right)}=\frac{1}{0.75}=\frac{100}{75}$
$=1.33$
$\Delta G ^{0}=- RT \ell nk _{ P }$
$=-8.31 \times 300 \times \ell n (1.33)=-710.45 \,J / mol$
$=-710\, J / mol .$