1. Tardigrade
  2. Question
  3. Chemistry
  4. The standard enthalpy change for the neutralisation of hydrocyanic acid and NaOH is Δ H° at 298=-2460 cal. Given that the standard enthalpy change for the neutralization of HCl and NaOH is Δ H=-13.71 kcal. What is the heat of ionization of HCN ?

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Q. The standard enthalpy change for the neutralisation of hydrocyanic acid and $NaOH$ is $\Delta H^{\circ}$ at $298=-2460\, cal$. Given that the standard enthalpy change for the neutralization of $HCl$ and $NaOH$ is $\Delta H=-13.71\, kcal$. What is the heat of ionization of $HCN ?$

Thermodynamics

Solution:

Heat of neutralization of $HCN$

= Total heat - heat of neutralization of strong base

$=-2.460-(-13.71)=11.25 kcal$ or $11250 cal$