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Q. The standard emf of a galvanic cell involving $3$ moles of electrons in its redox reaction is $0.59 \,V$. The equilibrium constant for the reaction of the cell is

KCETKCET 2010Electrochemistry

Solution:

$E_{\text {cell }}^{\circ} =\frac{0.0591}{n} \log K_{c}$

$0.59 =\frac{0.0591}{3} \log K_{c} \\ \frac{0.59 \times 3}{0.059} =\log K_{c}$

$\therefore \log K_{c} =30$

$K_{c} =$ antilog $30$

$=10^{30}$