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Q. The standard emf of a galvanic cell involving $2$ moles of electrons in its redox reaction is $0.59\, V$. The equilibrium constant for the redox reaction of the cell is

KCETKCET 2011Electrochemistry

Solution:

In a galvanic cell, $\Delta G^{\circ}=-n F E^{\circ}$ ...(i)

Relationship between $\Delta G^{\circ}$ and equilibrium constant

$\Delta G^{\circ}=-2.303 R T \log K_{p}$ ...(ii)

From Eqs. (i) and (ii), we get

$-2.303\, R T \log K_{p}=-n F E^{\circ}$

$\log K_{p}=\frac{n F E^{\circ}}{2.303 R T}=\frac{n E^{\circ}}{\frac{2.303 R T}{F}}$

$=\frac{2 \times 0.59}{0.059}=20$

$K_{p}= AL (20)$ ( AL =Antilog)

$K_{p}=10^{20}$