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  4. The standard deviation of the data 6,7,8,9,10 is

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Q. The standard deviation of the data $6,7,8,9,10$ is

Solution:

Mean $\bar{x}=\frac{6+7+8+9+10}{5}=8$
Variance $\sigma^{2}=\frac{1}{n} \in\left(x_{i}-\bar{x}\right)^{2}=2$
$\Rightarrow \sigma=\sqrt{2}=S. D$