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Chemistry
The spin-only magnetic moment [in units of Bohr magneton, (BM)] of Ni 2+ in aqueous solution would be (atomic number of Ni =28 )
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Q. The "spin-only" magnetic moment [in units of Bohr magneton, (BM)] of $Ni ^{2+}$ in aqueous solution would be (atomic number of $Ni =28$ )
Coordination Compounds
A
2.83
67%
B
4.90
33%
C
0
0%
D
1.73
0%
Solution:
$28^{ Ni } \rightarrow[ Ar ] 3 d^{8} 4 s^{2}$
Number of unpaired electrons $(n)=2$
$\mu=\sqrt{n(n+2)}=\sqrt{2(2+2)}=\sqrt{8} \approx 2.83$