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Q. The "spin-only" magnetic moment [in units of Bohr magneton, (BM)] of $Ni ^{2+}$ in aqueous solution would be (atomic number of $Ni =28$ )

Coordination Compounds

Solution:

$28^{ Ni } \rightarrow[ Ar ] 3 d^{8} 4 s^{2}$

image

Number of unpaired electrons $(n)=2$

$\mu=\sqrt{n(n+2)}=\sqrt{2(2+2)}=\sqrt{8} \approx 2.83$