1. Tardigrade
  2. Question
  3. Physics
  4. The speed of the sound in air is 333 ms-1. The fundamental frequency of the open pipe is 333 Hz. The second overtone of the open organ pipe can be produced with a pipe of length.

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Q. The speed of the sound in air is 333 $ms^{-1}.$ The fundamental frequency of the open pipe is 333 Hz. The second overtone of the open organ pipe can be produced with a pipe of length.

Electromagnetic Waves

Solution:

For second overtone
$ n_2 =\frac{3v}{2L} =2n_1$
Here v = speed of sound in air = 333 $ms^{-1}.$
$n_1$ = fundamental frequency of the open pipe= 333 Hz
$\therefore \frac{3 \times 333}{2L} = 3 \times 333 $
or $ \frac{1}{2L} = 1 $
or $ L = frac{1}{2} = 0.5\, m $