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Q. The speed of an electron having a wavelength of $10^{-10} m$ is

Dual Nature of Radiation and Matter

Solution:

By using $\lambda_{\text {electron }}=\frac{h}{m_{e} v}$
$\Rightarrow v=\frac{h}{m_{e} \lambda_{e}}$
$=\frac{6.6 \times 10^{-34}}{9.1 \times 10^{-31} \times 10^{-10}}$
$=7.25 \times 10^{6}\, m / s$