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Q. The speed of a boat in still water is $15 \, km \, h^{- 1}$ and the rate of current is $3 \, km \, h^{- 1}$ . The distance travelled downstream in $12$ minutes is

NTA AbhyasNTA Abhyas 2020Motion in a Straight Line

Solution:

Speed downstream $=\left(\right.15 \, + \, 3\left.\right)kmph=18kmph$
Distance travelled $=\left(18 \times \frac{12}{60}\right)km=\text{3.6}km$