Question

The specific conductivity of $N / 10 KCl$ solution at $20^{\circ} C$ is $0.0212 \,ohm ^{-1} cm ^{-1}$ and the resistance of cell containing this solution at $20^{\circ} C$ is $55 ohm$. The cell constant is

• A. $2.173\, cm ^{-1}$
• B. $1.166\, cm ^{-1}$
• C. $4.616\, cm ^{-1}$
• D. $3.324\, cm ^{-1}$

Answer 1

Answer: (B)

We know that

specific conductance $=$ cell constant $\times$ conductance

$\Rightarrow $ Cell constant $ =$ Resistance $\times$ specific conductance

$=0.0212 \times 55 $

$=1.166 \,cm ^{-1}$