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  3. Chemistry
  4. The specific conductivity of a solution containing 1.0g of anhydrous BaCl2 in 200 cm3 of the solution has been found to be 0.0058 S cm-1. Calculate the molar conductivity of the solution. (Molecular wt. of BaCl2 = 208).

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Q. The specific conductivity of a solution containing $1.0g$ of anhydrous $BaCl_2$ in $200 \,cm^3$ of the solution has been found to be $0.0058 \,S \,cm^{-1}$. Calculate the molar conductivity of the solution. (Molecular wt. of $BaCl_2 = 208)$.

Electrochemistry

Solution:

Molarity of $BaCl_2 = \frac{1\times 1000}{208 \times 200} = 0.024\,M$
Also, Normality of $BaCl_2= 0.024 \times 2 = 0.048\,N$
$( \because N = M \times$ Valency factor)
Now, $\wedge_{m} = k\times \frac{1000}{C_{M}} = \frac{0.0058\times1000}{0.024} $
$ = 241.67 \,S \,cm^{2} \,mol^{-1}$