Question

The specific conductivity of a saturated $AgCl$ solution is $1.26\times 10^{- 6}Scm^{- 1}$ If $K_{sp}$ of $AgCl$ is $x\times 10^{- 12},$ then value of $'x'$ is ?

Answer 1

$\Lambda_{m}^{\infty}\left(\right.AgCl\left.\right)=62+78=140$
$140=\frac{1 .26 \times 10^{- 6} \times 1000}{s}$
$s=9\times 10^{- 6}$
$K_{sp}=s^{2}=81\times 10^{- 12}$