1. Tardigrade
  2. Question
  3. Chemistry
  4. The specific conductance of 0.1 M NaCl solution is 3.2 × 10-3 S cm -1 . The resistance of the solution contained in the cell is found to be 125 Ω . The cell constant (in cm -1 ) will be equal to

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Q. The specific conductance of $0.1 \,M \,NaCl$ solution is $3.2 \times 10^{-3} \,S \,cm ^{-1} .$ The resistance of the solution contained in the cell is found to be $125 \,\Omega .$ The cell constant (in $cm ^{-1}$ ) will be equal to

Solution:

$\kappa=\frac{1}{R} \times \frac{1}{a}$
$\Rightarrow $ Cell constant, $\frac{l}{a}=\kappa \times R$
$=3.2 \times 10^{-3} \times 125=0.4 \,cm ^{-1}$