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Q. The specific conductance of $0.1 \, M\, NaCl$ solution is $1.06 \times 10^{-2} ohm ^{-1} cm ^{-1} .$ Its molar conductance in $ohm ^{-1} cm ^{2} mol ^{-1}$ is

Electrochemistry

Solution:

Applying, $\Lambda_{m}=\kappa \times \frac{1000}{\text { Molarity }}$

$=1.06 \times 10^{-2} \times \frac{1000}{0.1}=1.06 \times 10^{2} ohm ^{-1} cm ^{2} mol ^{-1}$