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Q. The sound level of a dog's bark is $50 \,dB$. The intensity of a rock concert is $10,000 $ times that of dog's bark. What is the sound level of the rock concert?

Solution:

$50 = 10 log (\frac {I}{I_o})$
$Also \,L \,= 10\, log$ $\left(\frac{10^{4}I}{I_{o}}\right)$
$\therefore L \,- \,50 = 10log(10^4) = 40$
$L \,= \,90 \,dB$