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  4. The sound intensity is 0.008 W / m 2 at a distance of 10 m from an isotropic point source of sound. The power of the source is:

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Q. The sound intensity is $0.008\, W / m ^{2}$ at a distance of $10\, m$ from an isotropic point source of sound. The power of the source is:

Waves

Solution:

$\frac{P}{4 \pi r^{2}}=I$ for an isotropic point sound source.
$\Rightarrow P=I .4 \pi r^{2}$
$=\left(0.008\, w / m ^{2}\right)\left(4 . \pi .10^{2}\right)$
$= 10$ watt