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Q. The solution set of the equation $| x -1|+| x |=2$ is

Continuity and Differentiability

Solution:

$|x-1|+|x|=2$
$\text { Case-1: } \text { If } x \in[0, \infty)$
$x-1+x=2 \Rightarrow x=3 / 2 \text { (solution) } $
$\text { Case-2: } \text { If } x \in[0,1)$
$ -x+1+x=2 \Rightarrow 1 \neq 2 \text { (no solution) } $
$\text { Case-3: } \text { If } x \in(-\infty, 0] $
$ -x+1-x=2 \Rightarrow x=\frac{-1}{2} \text { (solution) }$