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Q. The solution of nickel sulphate in which nickel rod is dipped is diluted to 10 times. The potential of nickel

Electrochemistry

Solution:

$Ni^{2+} + 2e^{-} \to Ni$
$E = E^{0} + \frac{0.059}{2} log \frac{\left[Ni^{2+}\right]}{\left[Ni\right]}$
$ = E^{0}+ \frac{0.059}{2} log\, 1\times10^{-1} $
$= \left(E^{0} - 0.03\right) volts$