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Chemistry
The solubility product of silver chromate is 4 × 10-12. The molar solubility of the salt is
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Q. The solubility product of silver chromate is $4 \times 10^{-12}$. The molar solubility of the salt is
Equilibrium
A
$1.0 \times 10^{-4} mol L^{-1}$
60%
B
$2 \times 10^{-10} mol L^{-1}$ '
20%
C
$1.0 \times 10^{-8} mol L^{-1}$
8%
D
$2 \times 10^{-6} mol L^{-1}$
12%
Solution:
Solubility $=(K_{sp}/4)^{1/3}\,mol\,L^{-1}$