1. Tardigrade
  2. Question
  3. Chemistry
  4. The solubility product of PbCl2 at 20°C is 1.5× 10-4 . Calculate the solubility.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The solubility product of $ PbCl_{2} $ at $ 20^{\circ}C $ is $ 1.5\times 10^{-4} $ . Calculate the solubility.

Haryana PMTHaryana PMT 2011

Solution:

$ PbCl_{2}\underset{S}{Pb^{2+}}\,+\underset{2S^{2}}{2Cl^{-}}$
$ K_{sp}=S\times (2\,\,S)^{2}4\,S^{3} $
$ S=\sqrt[3]{\frac{K_{sp}}{4}}=\sqrt[3]{\frac{1.5\times 10^{-4}}{4}}$
$=3.34\times {{10}^{-2}} $