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Chemistry
The solubility product of Hg2I2 is equal to
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Q. The solubility product of $ H{{g}_{2}}{{I}_{2}} $ is equal to
Rajasthan PET
Rajasthan PET 2010
A
$ [Hg_{2}^{2+}][{{I}^{-}}] $
B
$ [H{{g}^{2+}}][{{I}^{-}}] $
C
$ [Hg_{2}^{2+}]{{[{{I}^{-}}]}^{2}} $
D
$ [H{{g}^{2+}}]{{[{{I}^{-}}]}^{2}} $
Solution:
$ H{{g}_{2}}{{I}_{2}}(s) \rightleftharpoons Hg_{2}^{2+}+2{{I}^{-}} $
$ \therefore $ $ {{K}_{sp}}=[Hg_{2}^{2+}]{{[{{I}^{-}}]}^{2}} $