1. Tardigrade
  2. Question
  3. Chemistry
  4. The solubility product of chalk is 9.3 × 10-8 Calculate its solubility in gram per liter.

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The solubility product of chalk is $9.3 \times 10^{-8}$ Calculate its solubility in gram per liter.

Equilibrium

Solution:

$CaCO _{3} \rightleftharpoons Ca ^{2+}+ CO _{3}^{2-}$

Let the solubility of $CaCO _{3}$ be $S$ mole per liter

$\therefore K_{ sp }=\left[ Ca ^{2+}\right]\left[ CO _{3}^{2-}\right]=S . S$

$\therefore S=\sqrt{K_{ sp }}=\sqrt{9.3 \times 10^{-8}}=0.000304$ mol / liter

Solubility in $g / l =$ mole/liter $\times$ Molecular weight of $CaCO _{3}$

$=0.000304 \times 100=0.0304 $ gram/liter