Tardigrade
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Tardigrade
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Physics
The solid angle subtended by the periphery of an area 1 cm2 at a point situated symmetrically at a distance of 5 cm from the area is
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Q. The solid angle subtended by the periphery of an area $1 \,cm^2$ at a point situated symmetrically at a distance of $5 \,cm$ from the area is
Physical World, Units and Measurements
A
$2 \times 10^{-2}$ steradian
33%
B
$4 \times 10^{-2}$ steradian
44%
C
$6 \times 10^{-2}$ steradian
20%
D
$8 \times 10^{-2}$ steradian
3%
Solution:
Solid angle, $d\,\Omega=\frac{d\,A}{r^{2}}=\frac{1\,cm^{2}}{\left(5\,cm\right)^{2}}$
$=4 \times 10^{-2}$ steradian