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Q. The smallest temperature difference measured with a thermocouple of e.m.f. $30\,\mu VC^{-1}$ and a galvanometer of $50 \,\Omega$ and capable of measuring a minimum current of $3 \times 10^{-7}$ is

Current Electricity

Solution:

Using V = 1R we get V = $3 \times 10^{-7} \times 50$
Detectable temperature difference = $\frac{V}{E} = \frac{3 \times 10^{-7} \times 50}{30 \times 10^{-6}} = 0.5^\circ$