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Q. The slope of the normal at the point $(at^2, 2at)$ of the parabola $ y^2 = 4ax$ is

Conic Sections

Solution:

Tangent at $'t'$ is $ty= x+at^{2} $
Slope of the tangent $= \frac{1}{t} $
$ \therefore $ slope of normal $= -t $