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Q. The slope of tangent to the curve $y=f(x)$ at $(x, f(x))$ is $(2 x+1)$. If the curve passes through the point $(1,2)$, then the area bounded by the curve the $x$-axis and line $x=1$ is

Application of Integrals

Solution:

image
$\frac{ dy }{ dx }=2 x +1$
$y=x^2+x+C $
$2=2+C \Rightarrow C=0 $
$y=x^2+x$
$\text { Area }=\int\limits_0^1\left(x^2+x\right) d x=\frac{1}{3}+\frac{1}{2}=\frac{5}{6} .$