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Q. The sinusoidal potential difference $V_{1}$ shown in figure applied across a resistor $R$ produces heat at a rate $W$. What is the rate of heat dissipation when the square wave potential difference $V_{2}$ as shown in figure is applied across the resistor?Physics Question Image

Alternating Current

Solution:

Power $(P)=\frac{V_{\text{rms}}^{2}}{R}$
According to the problem
$w=\frac{\left(\frac{V_{0}}{\sqrt{2}}\right)^{2}}{R}$
for square wave $V_{\text{rms}}=V_{0}$
$W'=\frac{V_{0}^{2}}{R} $
$\frac{W'}{W}=2, $
$W'=2\, W$